(3/x-2)-(2x/x^2-4)=5/x+2

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Solution for (3/x-2)-(2x/x^2-4)=5/x+2 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x-((2*x)/(x^2))-2+4 = 5/x+2 // - 5/x+2

3/x-((2*x)/(x^2))-(5/x)-2-2+4 = 0

3/x-2*x^-1-5*x^-1-2-2+4 = 0

-4*x^-1 = 0 // : -4

x^-1 = 0

x naleu017Cy do O

x belongs to the empty set

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